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Write 14x as 11x+3x to factor the left-hand side. Add 7^2 on both sides to complete the square.
x=-3 and x=-11
Let's solve the equation twice! One time we will use the Zero Product Property and the other time we will complete the square.
To solve this equation with the Zero Product Property, we must first factor the left-hand side. To do that, we can use a generic rectangle and a diamond problem. We know that x^2 and 33 on the left-hand side goes into the lower left and upper right corner of the generic rectangle.
Notice that the product and sum are both positive. This means both factors must be positive. |c|c|c|c|c| [-1em] Product & ax(bx) & ax+bx & Sum & 14x? [0.2em] [-1em] 33x^2 & 3x(11x) & 3x+11x & 14x & âś“ [0.3em] When one factor is 3x and the other is 11x we have a product of 33x^2 and a sum of 14x. Now we can complete the diamond and generic rectangle.
Use the Zero Product Property
(I):LHS-3=RHS-3
(II):LHS-11=RHS-11
Complete the square
Calculate quotient
LHS-33=RHS-33
Split into factors
a^2+2ab+b^2=(a+b)^2
Calculate power
Subtract term
sqrt(LHS)=sqrt(RHS)
LHS-7=RHS-7
State solutions
(I), (II): Add and subtract terms