Core Connections Algebra 2, 2013
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Core Connections Algebra 2, 2013 View details
2. Section 3.2
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Exercise 115 Page 158

Practice makes perfect
a The graph describes the function expression |x-3|+1. To find when it's equal to 1 we should locate the point(s) on the graph where y=1.

The function value is 1 when x=3. The solution to the equation is therefore x=3.

b The solution set to the inequality is all x-values that make the function value less than or equal to 4. In the coordinate plane, let's draw the line y=4.

The x-values of every point on the graph that are beneath or equal to y=4 solves the inequality.

The points on the graph beneath y=4 are between x=0 and x=6 including the endpoints. We can write this as the following solution set. 0≤ x ≤ 6

c Now we want to find for which x-values |x-3|+1 is equal to 3. Start from y=3 on the y-axis and determine the point(s) on the graph that have this y-value.

The function value is 3 when x=1 and x=5. Therefore, the solutions to the equation are x=1 and x=5.

d Now we want to find all x-values where the function's value is greater than 2. Let's start by drawing the line y=2. Notice that we will dash the line since we are dealing with a strict inequality. This means any x that gives y=2 will not be included in the solution set.

The x-values of every point on the graph that is above y=2 solves the inequality.

The parts of the graph that satisfies the inequality are x less than 2 or x greater than 4. The solution set can be described with the following intervals x<2 and x>4