Core Connections Algebra 2, 2013
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Core Connections Algebra 2, 2013 View details
1. Section 1.1
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Exercise 5 Page 7

Practice makes perfect
a Angelica has two options.
  1. Input 6 into g(x) and then input its result into h(x).
  2. Input 6 into h(x) and then input its result into g(x).We cannot be sure which one is correct before we've tried. Let's try the second option, to calculate h(6) first.
    h(x)=x^2-6
    h( 6)= 6^2-6
    â–Ľ
    Evaluate right-hand side
    h(6)=36-6
    h(6)=30
    The output is 30. Now we will use it as the input for the other function, g(x).
    g(x)=sqrt(x-5)
    g( 30)=sqrt(30-5)
    â–Ľ
    Evaluate right-hand side
    g(30)=sqrt(25)
    g(30)=5
    The output of the function is 5. This is exactly what Angelica wanted. Therefore, this is the correct order of the functions: first h(x) and then g(x).
b
We want to find an input x that will give an output of -5 after passing through two functions consecutively. input x→function#1→function #2→ output -5To find x, we can think backwards. What input makes the second function equal to -5? We have two possibilities here. Either g(x) or h(x) is the second function. g(x)=-5 or h(x)=-5 Since we do not know the order of the functions, let's consider what would happen if g(x) was the second function. sqrt(x-5)=-5 The result of a square root can only be a positive number when working with real numbers. Therefore, the result of g(x) cannot be -5. Now let's consider what would happen if h(x) is second.
h(x)=-5
x^2-6=-5
â–Ľ
Solve for x
x^2=1
x=1
An input of x=1 gives us that h(x)=-5. Now, this value should be used as the output of the function g(x). Once again, this will form an equation that can be solved for x.
g(x)=1
sqrt(x-5)=1
â–Ľ
Solve for x
x-5=1
x=6
Therefore, it possible for Angelica to get a final output of -5 if she uses 6 as her input. She must also use g(x) and then h(x).