Core Connections Algebra 1, 2013
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Core Connections Algebra 1, 2013 View details
1. Section 6.1
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Exercise 4 Page 249

Practice makes perfect
a

Examining the diagram, we see that there is a positive association between the length of the paint and the pencil's weight — as the length of the paints increases, so does the weight of the pencil increase. Also, it appears that this association is linear with an outlier at x≈ 2.3.

b

There could be many reasons why the data has an outlier. Perhaps this particular pencil was of a different and heavier sort than the others?

c

In Sam's line of best fit we can identify the slope as 0.25. If we rewrite this as a fraction it is easier to talk about what the slope represents.

m=0.25 ⇔ m=1/4 The numerator shows the number of steps you take in the vertical direction when you take the number of steps given by the denominator in the horizontal direction. m=1/4 ⇔ m=rise/run Therefore, the slope tells us that the pencil's weight is expected to increase by 1 gram for every four centimeters of paint.
d

By substituting 11.5 instead of l in the equation from Part C, we can predict the weight of the teacher's pencil.

w=1.4+0.25l
w=1.4+0.25( 11.5)
â–¼
Solve for w
w=1.4+2.875
w=4.275
w≈ 4.3

The weight of the pencil should be about 4.3 grams.

e

The y-intercept shows the weight of the pencil when the length of the paint is 0 cm. This must mean that the pencil without any paint left still weighs 1.4 grams. Obviously, the wood underneath the paint has weight.