We must find the equation and the fifth term
t(5) of an arithmetic sequence with the given terms. Recall that an
arithmetic sequence is characterized by having an
addition or subtraction sequence generator. This is a constant number that is added or subtracted to the term to get the next term. Let's analyze the information we have so far.
… t(8)t(9)t(10)t(11)t(12)… 1056 ? ? ?? t(13) … 116 …
We can see that the sequence is decreasing, since the
8th term is
1056 but the
13th term is
116. With this information we know that a constant number
c is being subtracted. From the
8th term to the
13th term this happens
5 times, so we can write the equation
t(8)−5c=t(13). By solving it we can find the common difference
c.
t(8)−5c=t(13)
1056−5c=116
1056−5c−1056=116−1056
-5c=-940
-5-5c=-5-940
c=188
Since the common difference from term to term is
188, the general form of the equation for this sequence is
t(n)=t(1)−188(n−1). We still need to find what
t(1) is. We can use one of the values for the terms we know and solve for
t(1).
t(n)=t(1)−188(n−1)
t(8)=t(1)−188(8−1)
t(8)=t(1)−188⋅7
1056=t(1)−188⋅7
1056=t(1)−1316
1056+1316=t(1)−1316+1316
2372=t(1)
t(1)=2372
Having found the first term, we can write the equation for our sequence as
t(n)=2372−188(n−1). Finally, we need to find
t(5). Let's evaluate our expression and find this term.
t(n)=2372−188(n−1)
t(5)=2372−188(5−1)
t(5)=2372−188(4)
t(5)=2372−752
t(5)=1620