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We are given a table that shows a familiar pattern from geometry.
| x | 1 | 2 | 3 | 4 | 5 |
|---|---|---|---|---|---|
| y | 2 | 4 | 6 | 8 | 10 |
We calculated that the slope of the given equation is 2. Now, remember that the y-intercept is the y-value where the line crosses the y-axis. It occurs when x=0. Since the slope is equal to 2, we need to subtract 1 unit to x-coordinate and 2 units to y-coordinate of the first given point to obtain the previous point.
| (x_1,y_1) | (x-1,y-2) | (x_2,y_2) |
|---|---|---|
| (1,1) | (1- 1,2- 2) | (0,0) |
Notice that we obtain a point where x=0. This means that the function intercepts the y-axis at (0, 0). Therefore, the value of b is 0. Now that we have the slope and the y-intercept, we can write a function for the line that passes through the given points. y= 2x+ 0 → y=2x Now, recall the formula for the area of a triangle. A= b* h/2 In our case, the base is equal to x and the height 4. Let's substitute this values into the formula.
b= x, h= 4
Multiply
a* b/c=a/c* b
Calculate quotient
We get the same form as the function obtained with the given data. Therefore, x represents the base length and y the area of a triangle with height equal to 4.