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(3,-7)
In this system of equations, at least one of the variables has a coefficient of 1. Therefore, we will approach its solution with the Substitution Method. Observing the given equations, it looks like it will be simplest to isolate x in the first equation using the Properties of Equality.
(I): LHS-y=RHS-y
(I): Subtract terms
(II): x= -4-y
(II): Distribute 6
(II): a(- b)=- a * b
(II): Multiply
(II): LHS+24=RHS+24
(II): Add terms
(II): .LHS /(-4).=.RHS /(-4).
(II): a* b/c=a/c* b
(II): - a/- b=a/b
(II): a/a=1
(II): Identity Property of Multiplication
(II): Put minus sign in front of fraction
(II): Calculate quotient
Great! Now, to find the value of x, we need to substitute y=-7 into either one of the equations in the given system. Let's use the first equation.
(I): y= -7
(I): a-(- b)=a+b
(I): Add terms
The solution, or point of intersection, to this system of equations is the point (3,-7).