Big Ideas Math: Modeling Real Life, Grade 8
BI
Big Ideas Math: Modeling Real Life, Grade 8 View details
3. Linear Functions
Continue to next subchapter

Exercise 12 Page 293

Practice makes perfect

We are given a table that shows the length y in inches of a person's hair after x months.

Months, x Hair Length, y
0 11.0
3 12.5
6 14.0
Functions written in slope-intercept form follow a specific format. y= mx+ b In this form, m is the slope and b is the y-intercept. We need to identify these values using the given table. Let's start by substituting the points (0,11) and (3,12.5), into the slope formula and calculating m.
m = y_2-y_1/x_2-x_1
m=12.5- 11/3- 0
â–Ľ
Simplify right-hand side
m=1.5/3
m=0.5
We calculated that the slope of the given equation is 0.5, which means that each month the hair increases by 0.5 inches. Now, remember that the y-intercept is the y-value where the line crosses the y-axis. It occurs when x=0. From the table we can see that when x=0, the value of y= 11.
Months, x Hair Length, y
0 11.0
3 12.5
6 14.0

The function intercepts the y-axis at (0, 11), which means that there are 11 inches of hair in the beginning. Therefore, the value of b is 11. Now that we have the slope and the y-intercept, we can write a function for the line that passes through the given points. y= 0.5x+ 11

Recall the function obtained in Part A.

y= 0.5x+ 11 Here, y represents the hair length in inches and x the amount of months. The slope of the function represents that the amount of new hair each month and the y-intercept represents the amount of hair at the beginning. Therefore, the hair length at the beginning was 11 inches and it grows 0.5 each month.