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| Item | Model | Actual |
|---|---|---|
| House | Height: 6 ft | Height: 30 ft |
| Garden hose | Length: 12 ft | Length: 20 yd |
| Fountain | Depth: 20 cm | Depth: 1 m |
We want to find the missing dimension using the scale of 1:5. We can recall that a scale of a model is the ratio between any length on the model and the corresponding length on actual object. Next, we can consider the given table.
| Item | Model | Actual |
|---|---|---|
| House | Height: 6 ft | Height: 30 ft |
| Garden hose | Length: 12 ft | Length: 20 yd |
| Fountain | Depth: 20 cm | Depth: â–¡ m |
First, we can write that the depth scale factor is equal to the ratio of the depth of the model fountain to the depth of the actual fountain.
a*b/c= a* b/c
Cross out common factors
Simplify quotient
a * 1=a
a* b/c=a/c* b
a/b=.a /20./.b /20.
The model fountain has the depth of 15 meter. Finally, we can substitute 1:5 for the scale factor and 15 meter for the length of the model fountain in our formula. We can also represent the depth of the actual fountain with an arbitrary variable d. Let's solve our formula for d!
Substitute values
a:b = \dfrac a b
LHS * d=RHS* d
1/b* a = a/b
a/d* d = a
LHS * 5=RHS* 5
a/5* 5 = a
The actual fountain has the depth of 1 meter. Finally, we can complete our table.
| Item | Model | Actual |
|---|---|---|
| House | Height: 6 ft | Height: 30 ft |
| Garden hose | Length: 12 ft | Length: 20 yd |
| Fountain | Depth: 20 cm | Depth: 1 m |