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| Item | Model | Actual |
|---|---|---|
| House | Height: 6 ft | Height: 30 ft |
| Garden hose | Length: 12 ft | Length: 20 yd |
We want to find the missing dimension using the scale of 1:5. We can recall that a scale of a model is the ratio between any length on the model and the corresponding length on actual object. Next, we can consider the given table.
| Item | Model | Actual |
|---|---|---|
| House | Height: 6 ft | Height: 30 ft |
| Garden hose | Length: â–¡ ft | Length: 20 yd |
First, we can write that the length scale factor is equal to the ratio of the length of the model hose to the length of the actual hose.
a*b/c= a* b/c
Cross out common factors
The actual hose has the length of 60 feet. Finally, we can substitute 1:5 for the scale factor and 60 feet for the length of the actual hose in our formula. We can also represent the length of the model hose with an arbitrary variable l. Let's solve our formula for l!
Substitute values
a:b = \dfrac a b
LHS * 60=RHS* 60
1/b* a = a/b
Calculate quotient
a/60* 60 = a
Rearrange equation
The model hose has the length of 12 feet. Finally, we can complete our table.
| Item | Model | Actual |
|---|---|---|
| House | Height: 6 ft | Height: 30 ft |
| Garden hose | Length: 12 ft | Length: 20 yd |