Exercise 4 Page 329

Inequalities can be solved in the same way as equations, by performing inverse operations on both sides until the variable is isolated. The only difference is that when we divide or multiply by a negative number, we must reverse the inequality sign.

5q+2≥ -13

SubIneq

LHS-2≥RHS-2

5q+2-2≥-13-2

SubTerms

Subtract terms

5q≥ -15

DivIneq

.LHS /5.≥.RHS /5.

5q/5≥ -15/5

MovePartNumRight

a* b/c=a/c* b

5/5q≥-15/5

CalcQuot

Calculate quotient

q≥-3

The above tells us that all values of q that are greater than or equal to -3 will satisfy the inequality. Let's demonstrate the inequality by graphing the solution set on a number line. Notice that q can be equal to -3, which we show with a closed circle on the number line.