Exercise 24 Page 252

We are told that our school raised $6750, which accounted for 125% of the fundraising goal. We can find what number's 125% is equal to 6750 to find what the goal was. Recall that the percent equation is an equation in which the part is equal to the product of the corresponding percent and the whole. We can represent a is p percent of wwith the following equation. a= p% * wWe can find what number's 125% is equal to 6750 by substituting p%= 1.25 and a= 6750 into the formula and solve for w using the Properties of Equality.

a= p% * w

SubstituteII

p%= 1.25, a= 6750

6750= 1.25 * w

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Solve for w

DivEqn

.LHS /1.25.=.RHS /1.25.

6750/1.25=1.25* w/1.25

CancelCommonFac

Cancel out common factors

6750/1.25=1.25* w/1.25

SimpQuot

Simplify quotient

6750/1.25=w

CalcQuot

Calculate quotient

5400=w

RearrangeEqn

Rearrange equation

w= 5400

Knowing the value of w, let's look at the completed percent equation. 6750= 125% * 5400 We found that 6750 is 125 % of 5400. This means that the fundraising original goal was $5400.

Checking Our Answer

Checking Our Answer

We can use a model to check our answer.