Exercise 21 Page 143

To solve an equation, we should first gather all of the variable terms on one side and all of the constant terms on the other side using the Properties of Equality. In this case, the only variable term is already on the left-hand side of the equation, so we will start by subtracting 10.35 from both sides.

10.35 + 2.3h = - 9.2

CommutativePropAdd

Commutative Property of Addition

2.3h+10.35 = - 9.2

SubEqn

LHS-10.35=RHS-10.35

2.3h +10.35 - 10.35 = - 9.2 - 10.35

SubTerm

Subtract term

2.3h = - 19.55

DivEqn

.LHS /2.3.=.RHS /2.3.

2.3h/2.3 = - 19.55/2.3

MoveNegNumToFrac

Put minus sign in front of fraction

2.3h/2.3 =- 19.55/2.3

CalcQuot

Calculate quotient

h = - 8.5

The solution to the equation is h = - 8.5. We can check our solution by substituting it into the original equation.

10.35 + 2.3h = - 9.2

Substitute

h= - 8.5

10.35 + 2.3( - 8.5) ? = - 9.2

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Simplify

MultPosNeg

a(- b)=- a * b

10.35 - 2.3 * 8.5 ? = - 9.2

Multiply

Multiply

10.35 -19.55 ? =- 9.2

AddTerms

Add terms

- 9.2=- 9.2

Since the left-hand side is equal to the right-hand side, our solution is correct.