Practice Test
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Mean: 9
Median: 7
Mode: 6
Range: 20
Interquartile Range: 4
We want to find the mean, median, mode, range, and interquartile range of the given data set. 5,6,4,24,10,6,9,8
When the data are arranged in numerical order, the median is the middle value — or the mean of the two middle values — in a set of data. Let's arrange the given values and find the median. 4, 5, 6, 6 | 8, 9, 10, 24 Since there are 8 values, there is no one middle value. Thus, for this exercise, the median is the mean of the two middle values. Median: 6+ 8/2=7
The mode is the value or values that appear most often in a set of data. Arranging the data set from least to greatest makes it easier to see how often each value appears. Let's arrange the values before we find the mode. 4, 5, 6, 6, 8, 9, 10, 24 The value that appears most often is 6. Mode: 6
The range is the difference between the greatest and least values in a set of data. For our exercise, the greatest value is 24 and the least value is 4. Range: 24-4=20
We want to find the interquartile range of the given data set. 5,6,4,24,10,6,9,8 To do this we need to identify the quartiles.
Let's start by recalling the ordered data set from least to greatest value! 4, 5, 6, 6 | 8, 9, 10, 24 The median of the set is 7. This value divides the set into two halves. We have two middle values for each half. Thus, we need to calculate the mean of those middle values. Upper Quartile:& 9+ 10/2=9.5 Lower Quartile:& 5+ 6/2= 5.5 The last step to calculate the interquartile range is to calculate the difference between the upper and lower quartiles. Let's do it! Interquartile Range:& 9.5- 5.5= 4