Exercise 11 Page 394

Inequalities can be solved in the same way as equations, by performing inverse operations on both sides until the variable is isolated. The only difference is that when we divide or multiply by a negative number, we must reverse the inequality sign.

h-13 ≥ 7

AddIneq

LHS+13≥RHS+13

h-13+ 13 ≥ 7+ 13

AddTerms

Add terms

h≥ 20

We found that all values of h greater than or equal to 20 will satisfy the inequality. Now let’s graph the inequality on a number line. Since h can equal 20, we draw a closed circle at this point. Since h is all values greater than or equal to 20, we will shade the part of the number line that represents numbers greater than or equal to 20. This means that we shade to the right of our point at 20, including 20 with the closed circle.