Exercise 1 Page 329

We want to calculate the surface area of a square pyramid. Let's see the given measurements of the pyramid.

The net is made up of the square and triangles. Let's calculate the area of each polygon separately, starting with the square.

A=s^2

Substitute

s= 3

A= 3^2

CalcPow

Calculate power

A=9

The area of the base that is a square is 9 square feet. Now let's take a look at the triangles. Note that sides of the pyramid are congruent triangles. This means that they have the same area. Let's substitute the measures of the sides into the formula for the area of a triangle!

A=1/2b* h

SubstituteII

b= 3, h= 7

A=1/2* 3* 7

WriteDec

Write as a decimal

A=0.5* 3* 7

Multiply

Multiply

A=10.5

We found that the area of one triangle is 10.5 square feet. Since the triangles are congruent, the area of every triangle is 10.5 square feet. Now we have all the information that we need to find the total surface area of the square pyramid! Total Surface Area 9+ 10.5+ 10.5+ 10.5+ 10.5=51ft^2 The total surface area of the square pyramid is 51 square feet.