body{margin:0;} noscript{z-index: 10000; position: fixed; display: block; height: 100%; width: 100%; background: #fff;} noscript .fa{font-size: 40px; display:block; color: #daa520;} noscript div{margin-top: 6%; padding-left: 20px; padding-right: 20px; text-align: center;} ! You must have JavaScript enabled to use this site.

Big Ideas Math: Modeling Real Life, Grade 6

BI

Big Ideas Math: Modeling Real Life, Grade 6 View details

Cumulative Practice

Exercise 6 Page 340

Use the net of a solid to find the surface area of the square pyramid.

C

We want to calculate the surface area of a square pyramid. Let's see the given measurements of the pyramid.

We can use a net to calculate the surface area of the pyramid. Let's see the net!

The net is made up of the square and four triangles. Let's calculate the area of each polygon separately, starting with the square.

A=s^2

s= 3

A= 3^2

Calculate power

A=9

The area of the square base is 9 square inches. Now let's take a look at the triangles. Notice that sides of the pyramid are congruent triangles. This means that they have the same area. Let's substitute the measures of the sides into the formula for the area of a triangle!

A=1/2b* h

b= 3, h= 5

A=1/2* 3* 5

Multiply

A=7.5

We found that the area of one triangle is 7.5 square inches. Since the triangles are congruent, this means that the area of each triangle is 7.5 square inches. Now we have all the information that we need to find the total surface area of the square pyramid! Total Surface Area 9+ 7.5+ 7.5+ 7.5+ 7.5=39in.^2 The total surface area of the square pyramid is 39 square inches. This corresponds to the option C.

Subchapter links

Exercises