body{margin:0;} noscript{z-index: 10000; position: fixed; display: block; height: 100%; width: 100%; background: #fff;} noscript .fa{font-size: 40px; display:block; color: #daa520;} noscript div{margin-top: 6%; padding-left: 20px; padding-right: 20px; text-align: center;} ! You must have JavaScript enabled to use this site.

Big Ideas Math: Modeling Real Life, Grade 6

BI

Big Ideas Math: Modeling Real Life, Grade 6 View details

Chapter Review

Continue to next subchapter

Exercise 20 Page 335

To find the area calculate, one half the product of the height and the sum of the bases.

76ft^2

Practice makes perfect

Let's find the area of the given trapezoid. The area of a trapezoid is one half the product of the height and the sum of the bases.

By the segment addition postulate we can say that the right edge is 6+ 7= 13 feet. Let's rotate the figure to make it easier to see the height and the bases!

In the given trapezoid we can see, that the height is 8 feet and the bases are 13 and 6 feet. We can substitute them into the formula for the area of a trapezoid. Let's do it!

A=1/2h(b_1+b_2)

SubstituteValues

Substitute values

A=1/2( 8)( 13+ 6)

▼

Evaluate right-hand side

Add terms

A=1/2(8)(19)

Multiply

A=1/2* 152

MoveRightFacToNumOne

1/b* a = a/b

A=152/2

Calculate quotient

A=76

The area of the trapezoid is 76 square feet.

Subchapter links

1 Areas of Parallelograms p.333

2 Areas of Triangles p.334

3 Areas of Trapezoids and Kites p.335

4 Three-Dimensional Figures p.336

5 Surface Areas of Prisms p.336

6 Surface Areas of Pyramids p.337

7 Volumes of Rectangular Prisms p.337