Big Ideas Math: Modeling Real Life, Grade 6
BI
Big Ideas Math: Modeling Real Life, Grade 6 View details
4. The Distributive Property
Continue to next subchapter

Exercise 14 Page 225

Practice makes perfect

We want to find the perimeter of the given triangle.

Error loading image.

The perimeter measures the distance around the outside of a two-dimensional figure. To find the perimeter, we can add all the lengths. 8cm+7.25cm+7.2cm=22.45cm The perimeter of the triangle is 22.45 centimeters.

We want to find the area of the given rectangle.

Imagine that each square inside the rectangle is an square unit .Since the square units cover the rectangle exactly, the number of square units will be equal to the area of the rectangle. The rectangle is formed by 28 squares, so the area of the rectangle is 28 square units.

We want to find the area and perimeter of the given rectangle.

Let's recall the formula for the area of a rectangle! A=l * w In this formula, l is the length and w is the width of the rectangle. The given triangle has a length of 8 inches and a width of 2 inches. We can substitute these values into the above formula to find the area.
A=l * w
A= 8* 2
A=16
The area of the rectangle is 16 square inches. Now, we will calculate the perimeter by using the formula for the perimeter of a rectangle. P=2l +2 w Since we know the value of l and w for the given rectangle, we can substitute them into the formula to find the perimeter.
P=2l +2 w
P=2( 8)+2( 2)
P=16+4
P=20
The perimeter is 20 inches.