Big Ideas Math Integrated I, 2016
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Big Ideas Math Integrated I, 2016 View details
2. Inductive and Deductive Reasoning
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Exercise 39 Page 457

Is the formula going to be a linear equation or a quadratic equation? How can you find out?

a_n=n(n+1)

Practice makes perfect

Inductive reasoning means we find a pattern for specific cases and then make conjectures for the general case. Let's make a sequence for the sum of the first positive even integers. 2&=2 2+4&=6 2+4+6&=12 2+4+6+8&=20 2+4+6+8+10&=30 2+4+6+8+10+12&=42 Next we have to look for a pattern in how the sequence increases, which is called the first difference.

As we can see, the value by which the sequence increases starts at 4 and then we add 2 to each increment as we move along the sequence. This means the formula cannot be a linear equation. If the second difference is a constant, we know the formula will be a quadratic equation.

The second difference is a constant, which means this is a quadratic equation of the form a_n=an^2+bn+c. To determine the equation we have to find the values of a, b, and c. Note that c is the sequence value when n=0. Therefore, by going backward from the sequence first number using the established pattern, we can find c.

When we know that c=0, we can write the equation. a_n=an^2+bn ⇔ a_n=n(an+b) To find the value of a and b we should create a system of equations using two of the ordered pairs. We will use ( 1,2) and ( 2,6). 2= 1(a( 1)+b) 6= 2(a( 2)+b) ⇒ 2=a+b 6=4a+2b Let's solve this system of equations.

2=a+b 6=4a+2b
2-b=a 6=4a+2b
2-b=a 6=4( 2-b)+2b
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(II): Solve for b
2-b=a 6=8-4b+2b
2-b=a 6=8-2b
2-b=a - 2=- 2b
2-b=a 1=b
2-b=a b=1

Having solved for b, we can substitute this value in the first equation to find a.

2-b=a b=1
2- 1=a 1=b
1=a 1=b

(I), (II): Rearrange equation

a=1 b=1

Now that we know the value of a and b, we can write the equation a_n=n((1)n+1) ⇒ a_n=n(n+1)