Exercise 21 Page 456

We are given the following pair of true statements. &1. if x<- 2, then |x|>2 &2. if x > 2, then |x|>2We are asked to use the Law of Syllogism to write a new conditional statement that follows from the given pair of statements. Let's start by recalling the Law of Syllogism. &1. If hypothesis p, then conclusion q. [0.5em] &2. If hypothesis q, then conclusion r. &3. If hypothesis p, then conclusion r. According to this law, if the first and the second statements are true, then the third statement is true. Now we can take a closer look at the given two conditional statements. Let's do it! &1. if x<- 2, then |x|>2 &2. if x > 2, then |x|>2 Note that the hypothesis of the second conditional statement does not match the conclusion of the first conditional statement. This means that we cannot use the Law of Syllogism to write a third conditional statement.