Does substituting the point into every equation in the system result in true statements?
No
Practice makes perfect
To determine if a point satisfies an equation, we substitute the point into the equation and simplify. If the resulting statement is true, the point is a solution of the equation. For systems of equations, we can use the same method, but substituting the point must create true statements in every equation in the system. Let's test the given point.
One of our resulting statements, 3≠- 3, is not true. The point (- 1,3) satisfies (I) but does not satisfy (II). Because one of the statements is not true, the point (- 1,3) is not a solution to the system.
