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What is the maximum weight that can be carried by the elevator?
Consider the results in Part A.
Inequality: 75x+40y≤ 1800
Graph:
See solution.
We want to write and graph an inequality for the given situation. Let's recall the given information.
Large Boxes:& 75 lb Small Boxes:& 40 lb Delivery Person:& 200 lb Weight Limit:& 2000 lb Let x be the number of large boxes and let y be the number of small boxes. By using the given information, we will first write an inequality in an organized table.
| Verbal Expression | Algebraic Expression |
|---|---|
| Weight of x large boxes (lb) | 75 x |
| Weight of y small boxes (lb) | 40 y |
| Weight of the delivery person (lb) | 200 |
| Total weight (lb) | 75 x+ 40 y+ 200 |
| Total weight is less than or equal to 2000 lb. | 75 x+ 40 y+ 200≤ 2000 |
| x-intercept | y-intercept | ||
|---|---|---|---|
| Substitution | Point | Substitution | Point |
| 75x+40( 0)=1800 | (24,0) | 75( 0)+40y = 1800 | (0,45) |
Next, we will plot the intercepts and draw the boundary line that passes through these points. Note that the number of boxes cannot be negative, so the line will be restricted by the axes. Additionally, since the inequality is non-strict, the line will be solid.
Finally, we will decide which side of the line we should shade. We will choose a point at either side of the line and substitute it into the inequality. If it satisfies the inequality, we shade the region that contains the point. Otherwise, we shade the other region. Let (0,0) be our test point!
x= 0, y= 0
Zero Property of Multiplication
Therefore, we will shade below the line.
There can be more than one reason why some solutions of the inequality might not be practical in real life. One of them can be that the number of the boxes must be positive whole numbers. Besides, a delivery person cannot take 10.5 large boxes and 20.5 small boxes.