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Nonvertical lines are parallel if and only if they have the same slope, and they are perpendicular if and only if their slopes are negative reciprocals.
Value of a for Parallel Lines: - 23
Value of a for Perpendicular Lines: 6
In order to determine the value of a, we need to know the slopes of the equations. We will therefore first isolate the y-variables in both equations so that they will be in slope-intercept form and we will be able to determine their slopes. ccc Given Form && Slope-Intercept Form [0.8em] 6y=-2x+4 &⇒ & y= -1/3x+2/3 2y=ax-5 &⇒ & y= a/2x-5/2 As a result, the slope of the first line is - 13 and the slope of the second line is a2. Now that we know the slopes of the lines, we can start with finding the value of a such that the lines are parallel.
We learned that nonvertical lines are parallel if and only if they have the same slope.
m_1= -1/3, m_2= a/2
LHS * 3=RHS* 3
LHS * 2=RHS* 2
.LHS /3.=.RHS /3.
Rearrange equation
As a result, the lines will be parallel when the value of a is - 23.
We also know that nonvertical lines are perpendicular if and only if their slopes are negative reciprocals. In other words, the product of the slopes must be -1. l_1⊥ l_2 ⟺ m_1 * m_2 = -1 Using the statement above, we can find the value of a.
m_1= -1/3, m_2= a/2
Put minus sign in numerator
Multiply fractions
LHS * 6=RHS* 6
LHS * (- 1)=RHS* (- 1)
We found that the lines will be perpendicular if the value of a is 6.