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Substitute ( 1,6) & ( 2,2)
Subtract terms
a/1=a
The slope of the given line — and, consequently, of the parallel line — is - 4. We can write a partial equation of our line using the slope-intercept form.
Now that we know that b= 19, we can write the equation of our line. y=- 4x+ 19
m_1* m_2=- 1
From Part A, we know that the slope of the given line is - 4. We can substitute - 4 for m_1 into the equation to find m_2, the slope of the perpendicular line.
m_1= - 4
.LHS /(- 4).=.RHS /(- 4).
- a/- b=a/b
The slope of the perpendicular line is 14. We can write the partial equation of this line by recalling the slope-intercept form. y= mx+ b ↓ y= 1/4x+ b Next, by substituting the given point ( 4, 3) into the equation, we can find the y-intercept b.
Now that we know that b= 2, we can write the equation of our line. y=1/4x+ 2