Big Ideas Math Integrated I, 2016
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Big Ideas Math Integrated I, 2016 View details
4. Graphing Linear Equations in Standard Form
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Exercise 38 Page 134

First, find the intercepts in terms of k.

The value of k can be any number divisible by 15. See solution.

Practice makes perfect

The x- and y-intercepts are the points where a relation crosses the x- and y-axes. To find the x-intercept, we need to find the value of x when y=0, and vice versa for the y-intercept. We can solve for the intercepts in terms of k first.

3x+5y=k
3x+5( 0)=k
3x+0=k
3x=k
x=k/3

The x-intercept of the equation is x= k3. Since we know that the intercepts are integers, k must be divisible by 3.

3x+5y=k
3( 0)+5y=k
0+5y=k
5y=k
y=k/5

The y-intercept of the equation is y= k5. Because this intercept must also be an integer, k must be divisible by 5 as well. Knowing that k must be divisible by both 3 and 5, we can say that it must be divisible by their Least Common Multiple, 15. Therefore, k is any integer that divides evenly by 15.