The given equation represents a straight line and it crosses both axes at some point. We were given the following equation.
x+ y=30
We will fill in the boxes with the coefficients of x and y. First, let's find the coefficient of x.
Coefficient of x
We are given that the x-intercept is -10. This corresponds with the point (-10,0). We can substitute this information into the given equation to solve for our coefficient of x.
This means that the coefficient of x is -3. Now we can write our equation in the following form.
-3x+ y=30
Coefficient of y
To find the coefficient of y, we will go through a similar process. We are given that the y-intercept is the point (0,5). We can substitute this point into the equation and solve.
