Big Ideas Math Integrated I, 2016
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Big Ideas Math Integrated I, 2016 View details
4. Graphing Linear Equations in Standard Form
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Exercise 24 Page 133

Practice makes perfect
a The given equation represents the total cost, where x is the number of short-sleeved shirts and y the number of long-sleeved shirts.

10x+12y=300 In order to graph the equation, we will first determine the intercepts. Let's start with the x-intercept. To find it, we will substitute 0 for y and solve the equation for x.

10x+12y=300
10x+12( 0)=300
â–¼
Solve for x
10x+0=300
10x=300
x=30

The x-intercept is at the point (30,0). For the y-intercept, we will substitute 0 for x and solve it for y.

10x+12y=300
10( 0)+12y=300
â–¼
Solve for y
0+12y=300
12y=300
y=25

The y-intercept is at the point (0,25). Finally, we will plot the intercepts and connect them to graph the equation. Notice that the number of the shirts cannot be negative, and thus our graph will be restricted to the first quadrant.

The x-intercept shows that we can order 30 short-sleeved shirts when we do not order any long-sleeved shirts. Similarly, the y-intercept shows that we can order 25 long-sleeved shirts when we do not order any short-sleeved shirts.

b In order to find how many long-sleeved shirts we can order when 12 short-sleeved shirts are ordered, we will substitute 12 for x into the equation. Then, we will solve it for y.

10x+12y=300
10( 12)+12y=300
120+12y=300
12y=180
y=15

As a result, we can order 15 long-sleeved shirts if we want 12 short-sleeved shirts.