Rewriting the equation from the given graph, we can determine that the sum of the rectangle's length and width is 20 inches.
y=20-x ⇔ x+y=20
If we substitute this into the equation x+y= P2, we can solve for the perimeter.
Te perimeter of the first rectangle is 40 inches. We are told that the perimeter of the second rectangle is 10 inches less than the perimeter of the first rectangle. This means we can calculate the perimeter of the second rectangle.
40-10=30 inches
This means that the sum of the rectangle's length and width is half of this, so 302=15 inches. We can now write a function that describes the second rectangle's width and length.
y+x=15 ⇔ y=15-x
Let's graph this. Notice that the endpoints are left open, as neither the width nor the length can be 15 inches.
b Let's graph both of the lines on the same coordinate plane and compare.
Comparing the graphs, we can see that both slopes are equal. We can also see that the blue graph's endpoints are closer to the origin.
