3y=-x-3 &⇔ y=- 13x-1
2y-14=4x &⇔ y=2x+7
4x-3-y=0 &⇔ y=4x-3
x-12=-3y &⇔ y=- 13x+4
Now we can graph the lines on a coordinate plane by identifying the y-intercept and slope of each equation. We will also be able to identify the enclosed shape formed by the lines.
Looking at the graph we identify a quadrilateral. Since the blue and purple line have the same slope, they are parallel lines. This means the quadrilateral is a trapezoid.
b We can tell that the green and the red lines are not parallel, as they get closer to each other in the first quadrant. However, the purple and blue lines are parallel. Looking at the functions of the parallel lines, we can see that as they have the same slope and different y-intercepts.
