We should find the coordinates of E', F' and G'. To do that we need to know the translation rule from quadrilateral DEFG to quadrilateral D'E'F'G'. We know that the preimage D has the coordinates (-1,2) and that the image D' has (-2,-2). We will graph them in a coordinate system to examine the translation.
To get from the preimage D to the image D', we will have to move 1 unit to the left and 4 units down.
Moving left on the x-axis is equivalent to subtract from the x-value and moving down is the same as to subtract from the y-value. Therefore, our translation rule will be as follows.
(x,y) → (x-1,y-4)
Now we will use the translation rule on the preimages E, F and G to get the images E', F' and G'.
ccc
(x,y) &→& (x-1,y-4) [0.5em]
E(-2,0) &→& E'(-3,-4)
F(-1,-1) &→& F'(-2,-5)
G(1,3) &→ & G'(0,-1)
The coordinates for the images are E'(-3,-4), F'(-2,-5), and G'(0,-1).
