Exercise 20 Page 548

Before we try to translate the given points, let's draw the triangle △ PQR on a coordinate plane using the given points. This triangle will be our preimage.

Now that we have the preimage, we can create the image using the translation (x,y) → (x-1,y+3). This translation tells us that for every point in △ PQR, we should subtract 1 from the x-coordinate and add 3 to the y-coordinate. ccc (x,y) &→ &(x-1,y+3) [0.8em] P(-2,3) &→ & P'(-2-1,3+3) = P'(-3,6) Q(1,2) &→ & Q'(1-1,2+3) = Q'(0,5) R(3,-1) &→ & R'(3-1,- 1+3)= R'(2,2) Now we have the points for the image. Let's add them to the same coordinate plane as the preimage.