Note that you are translating â–³ A'B'C' and not â–³ ABC.
A''(-1, 4), B''(3, 6), and C''(2, -2)
(x,y) → (x-1,y+1)
Practice makes perfect
We have already made one transformation of â–³ ABC to â–³ A'B'C'.
Let's perform the second translation of â–³ A'B'C' by moving all of the vertices 3 units to the right and 4 units up.
To make the diagram less messy, we will hide the middle step — the first of the two transformations — and then count the number of vertical and horizontal steps between two corresponding vertices.
As we can see, the original triangle would have to be translated horizontally by 1 unit to the left and vertically by 1 unit up.
(x,y) → (x-1,y+1)
This makes vertices of the final image A''(-1, 4), B''(3, 6), and C''(2, -2).
