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Big Ideas Math Integrated I, 2016

BI

Big Ideas Math Integrated I, 2016 View details

Chapter Review

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Exercise 8 Page 44

Distribute on the left-hand side and isolate the variable.

x=18

Practice makes perfect

To solve an equation, we need to isolate the variable. Before we can do that, we must distribute on the left-hand side.

3/2(x-2)-5=19

Distribute 3/2

3/2* x-3/2*2-5=19

FracMultDenomToNumber

a/2* 2 = a

3/2* x-3-5=19

MoveRightFacToNum

a/c* b = a* b/c

3x/2-3-5=19

Subtract term

3x/2-8=19

LHS+8=RHS+8

3x/2=27

LHS * 2=RHS* 2

3x=54

.LHS /3.=.RHS /3.

3x/3=54/3

Calculate quotient

x=18

The solution to the equation is x=18. We can check our solution by substituting it into the original equation and simplifying.

3/2(x-2)-5=19

x= 18

3/2( 18-2)-5? =19

▼

Simplify LHS & RHS

Subtract term

3/2* 16-5 ? =19

MoveRightFacToNum

a/c* b = a* b/c

3 * 16/2-5 ? =19

Multiply

48/2-5 ? =19

Calculate quotient

24-5 ? =19

Subtract term

19=19 ✓

Because the left-hand side and right-hand sides are equal, we know that our solution is correct.

Subchapter links

1 Solving Simple Equations p.44

2 Solving Multi-Step Equations p.44

3 Solving Equations with Variables on Both Sides p.45

4 Solving Absolute Value Equations p.45

5 Rewriting Equations and Formulas p.46