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Raise each side of the equation to a power equal to the index of the radical to eliminate the radical.
x=0 and x=4
Solving a radical equation usually involves three main steps.
Now we can analyze the given radical equation.
sqrt(10x+9)=x+3
LHS^2=RHS^2
( sqrt(a) )^2 = a
(a+b)^2=a^2+2ab+b^2
Multiply
Calculate power
LHS-10x=RHS-10x
LHS-9=RHS-9
Rearrange equation
We obtained a quadratic equation. There are many ways to solve a quadratic equation. We will solve it by factoring it.
Factor out x
Use the Zero Product Property
(II): LHS+4=RHS+4
Next, we will check the solutions by substituting 0 and 4 for x into the original equation. If the substitution produces a true statement, we know that our answer is correct. If it does not, then it is an extraneous solution. Let's first check the 0.
x= 0
Zero Property of Multiplication
Add terms
Calculate root
Because our substitution produced a true statement, we know that our answer, x=0, is correct. Let's check now the 4.
Because our substitution produced a true statement, we know that our answer, x=4, is correct.