Sign In
Try to solve the equation using different approaches. Is there one approach that is easier than the others?
Preferred method: The graphical approach is preferred.
Explanation: See solution.
Solution: x=6
We will try different methods of solving the given equation, then decide which is the easiest for us to use.
LHS+sqrt(x-2)=RHS+sqrt(x-2)
LHS^2=RHS^2
( sqrt(a) )^2 = a
(a+b)^2=a^2+2ab+b^2
( sqrt(a) )^2 = a
A numerical approach is basically trial-and-error. By substituting appropriate values of x in the equation, we can find an approximate or exact solution. However, to use this approach, we must have some basic idea of what the solution might be. Let's show an example. sqrt(x)=12 We know that sqrt(9)=3 and sqrt(16)=4, so the solution to the radical equation is between 3 and 4. However, for the given equation, there is no real clue as to where the solution might be. Therefore, this is not a good way of solving the equation.
To solve a radical equation graphically, we draw the left-hand side and right-hand side of the equation as individual graphs. f(x)= sqrt(x+3)-sqrt(x-2) and g(x)= 1 By identifying the x-value where these graphs intersect, we can solve the equation.
The solution is x=6. As we can see, the graphical approach is preferred in this instance.