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Start by identifying a, b, and c. The maximum value of the given quadratic function is g ( - b2a ).
Maximum Value: 35
Increasing Interval: To the left of x=4
Decreasing Interval: To the right of x=4
Note that the function is already written in standard form, g(x)=ax^2+bx+c, where a, b, and c are either positive or negative numbers. g(x)=- 2x^2+16x+3 To solve the problem and draw the graph, we will follow four steps.
Let's get started.
Let's identify the values of a, b, and c in the given quadratic function.
The axis of symmetry is a vertical line with equation x=- b2a. Since we already know the values of a and b, we can substitute them into the formula.
The axis of symmetry of the parabola is the vertical line with equation x=4. To calculate the vertex, we can write the expression for the vertex by stating the x- and y-coordinates in terms of a and b. Vertex:& ( - b/2a, g( - b/2a ) ) Note that the formula for the x-coordinate is the same as the formula for the axis of symmetry, which is x=4. Thus, the x-coordinate of the vertex is also 4. To find the y-coordinate, we need to substitute 4 for x in the given equation.
We found the y-coordinate, and now we know that the vertex is (4,35).
Since a=- 2 is less than 0, the function increases to the left of the maximum value and decreases to the right of the maximum value, which we know occurs at 4. This means that g(4)=35 will be the maximum value of g. Minimum value:& 35 Increasing Interval:& To the left of 4 Decreasing Interval:& To the right of 4
We will now plot a point on the curve by choosing an x-value and calculating its corresponding y-value. Let's try x=0.
When x=0, we have g(0)=3. Thus, the point (0,3) lies on the curve. Let's plot this point and reflect it across the axis of symmetry.
Note that both points have the same y-coordinate. Finally, we will sketch the parabola which passes through the three points. Remember not to use a straightedge for this!