Big Ideas Math Algebra 2, 2014
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Big Ideas Math Algebra 2, 2014 View details
5. Making Inferences from Sample Surveys
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Exercise 23 Page 632

What is the margin of error for this random sample? How does it relate to the sample size?

About 453 residents

Practice makes perfect
A developer claims that the percent of city residents who favor building a new football stadium is between 52.3 % and 61.7 %. We need to find the number of residents surveyed. First, recall that when a random sample of size n is taken from a large population, the margin of error can be approximated with the following formula. Margin of error = ± 1/sqrt(n) Now, this means that if the percent of the sample responding a certain way is p, then the percent of the population who would respond the same way is likely to be less than the margin of error away from p. Therefore, it is likely to be between the two following values. p- 1/sqrt(n) and p+ 1/sqrt(n)Notice that we already know both of the values, since we were told that the percent of city residents who favor building a new football stadium is between 52.3 % and 61.7 %. p+ 1/sqrt(n) &= 61.7 % p- 1/sqrt(n) &= 52.3 % Let's now subtract the two equalities and then simplify. This will being us closer to finding the value of n.
p+ 1/sqrt(n) - (p- 1/sqrt(n) ) = 61.7 - 52.3 %
p+ 1/sqrt(n) - (p- 1/sqrt(n) ) = 9.4 %
p+ 1/sqrt(n) -p+ 1/sqrt(n) = 9.4 %
1/sqrt(n) + 1/sqrt(n) = 9.4 %
2/sqrt(n) = 9.4 %
Having simplified both sides, here is the equation we got. 2/sqrt(n) = 9.4 % Let's solve the equation for n.
2/sqrt(n) = 9.4 %
Solve for n
2/sqrt(n) = 0.094
2 = 0.094sqrt(n)
2/0.094 = sqrt(n)
(2/0.094)^2=n
n = (2/0.094)^2
n = 452.693526...
n ≈ 453
The size of the sample, which is the number of residents surveyed, is approximately 453 people.