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y= 15
LHS-15=RHS-15
Add and subtract terms
Rearrange equation
Use the Quadratic Formula: a = -0.08, b= 1.6, c= -5
Calculate power and product
Add and subtract terms
Calculate root
x ≈ -1.6 ± 0.98/-0.16 | |
---|---|
x_1 ≈ | x_2 ≈ |
-1.6 + 0.98/-0.16 | -1.6 - 0.98/-0.16 |
-0.62/-0.16 | -2.58/-0.16 |
3.88 | 16.12 |
Since the exercise states that the model works from 1995 to 2014, both solutions are viable. The first solutions x ≈ 3.88, says that about 3.88 years since 1995, in 1998, there were 15 tons of trout caught. The second solution, x_2 ≈ 16.12, tells us that 15 tons of trout were caught in 2011.
The lake's ecology is a limiting factor in how many fish can be caught. Among the factors that will limit the amount of fish in a lake are: size, availability of food, oxygen (DO), predators, death rate, and the trout's reproduction rate. Furthermore the number of fisher people and their ability to catch trout can limit the number caught.
Weather or not the quadratic model given took into account these other factors will determine if it is a viable model. Let's have a look at the model again, but add in some elements from the lake situation.
It is possible that it is effective for a few more years, but eventually the quadratic will have negative solutions and negative years, which limit it's ability to model real world for an extensive period of time. After 2005 the tons of trout caught will start to decline and after 2021 the function gives us negative values for x.