Big Ideas Math Algebra 1, 2015
BI
Big Ideas Math Algebra 1, 2015 View details
Chapter Test
Continue to next subchapter

Exercise 11 Page 229

Practice makes perfect
a Let's consider the given data!
Advertising (dollars), x Yearly attendance, y
500 400
1000 550
1500 550
2000 800
2500 650
3000 800
3500 1050
4000 1100
We are asked to find an equation of the line of best fit for the above data. We will begin by entering the values into list. We press the button STAT on the calculator. After that we choose Edit and then enter the x-values in column L1 and the y-values in column L2.
=Illustration of the STAT menu on the calculator
Illustration of the lists on the calculator with six ordered pairs written

To view the linear regression analysis of the dataset we press STAT, scroll to right to view the CALC options, and then choose the fourth option in the list, LinReg(ax+b).

Illustration of the STAT + CALC menu on the calculator
Illustration of the LinReg(ax+b) window on the calculator

We find the equation of the line of best fit by substituting the values for a and b into the slope-intercept form equation. y= ax+ b ⇓ y= 0.19x+ 309

b The correlation coefficient is the value stated as r on the screen of the calculator.
Illustration of the LinReg(ax+b) window on the calculator

For our case, the correlation coefficient is approximately 0.94. Since it is close to 1, there is a strong correlation between the advertising and the yearly attendance.

c As we stated in Part B, there is strong correlation between the variables in the given data.

r≈ 0.94 ⇒ Strong correlation Therefore, we should expect that the points in the scatter plot of the residuals will be close to and evenly dispersed about the horizontal axis.

d Let's recall what it means that two variables have a causal relationship.

A causal relationship exists when one variable causes a change in another variable.

If the advertising is increased, more people learn about the festival and that will make more people visit. Therefore, there is a causal relationship between the variables.

e Notice that the value we are asked to predict is outside the range of known values. Therefore, we should use the equation of the line of best fit we found in Part A. y=0.19x+309 We will substitute 2000 for y into the equation and solve it for x. Let's do it!
y=0.19x+309
2000=0.19x+309
Solve for x
1691=0.19x
8900=x
x= 8900
The amount that must be spent on advertising to get 2000 people to attend the festival is $8900.