Big Ideas Math Algebra 1, 2015
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Big Ideas Math Algebra 1, 2015 View details
5. Analyzing Lines of Fit
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Exercise 20 Page 207

Practice makes perfect
a To perform a linear regression, we first have to enter the values into lists. Push STAT, choose Edit, and then enter the values in the first two columns.
To do a linear regression we push STAT, scroll right to CALC, and then choose the fourth option in the list, LinReg.


We can see the equation for the line of best fit. y=4.9x-37.7

b We can find the correlation coefficient r on the screen with linear regression results.

Therefore the correlation coefficient is approximately r=0.936. This tells us that correlation is both positive and very strong. We know that it is strong because it is extremely close to 1. A correlation of 1 would be a direct correlation explained by a line that goes through all of the points.

c Since the data shows the cost in thousands of dollars and the length in feet, the slope of 4.9 means that for every 1 foot, a sailboat increases in value by $4 900. Meanwhile, the y-intercept has no interpretation because a sailboat cannot have the length of 0 feet.
d In order to estimate the cost of a sailboat that is 20 feet long, we have to substitute 20 for x in the equation for the line of the best fit.
y=4.9x-37.7
y=4.9( 20)-37.7
y=98-37.7
y=60.3
This means that the cost of the sailboat with a length of 20 feet is equal to $60 300.
e In order to estimate the length of a sailboat that costs $147 000, we have to substitute 147 for y in the equation for the line of the best fit.
y=4.9x-37.7
147=4.9x-37.7
184.4=4.9x
x=37.63265...
x≈37.6
This means that the length of a sailboat that costs $ 147 000 is approximately equal to 37.6 feet.