Big Ideas Math Algebra 1, 2015
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Big Ideas Math Algebra 1, 2015 View details
1. Measures of Center and Variation
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Exercise 7 Page 590

Practice makes perfect
a We want to find mean, median, and mode of the given data set.

13 , 30 , 16 , 19 , 20 , 22 , 25 , 31 Let's proceed to finding the mean, median, and mode.

Mean

The mean of a data set x is calculated by finding the sum of all of the values in the set and then dividing by the number of values in the set. In this case, there are 8.
Mean=Sum of values/Number of values
x=13+30+16+19+20+22+25+31/8
x=176/8
x=22
The mean of the set is 22.

Median

When the data are arranged in numerical order, the median is the middle value — or the mean of the two middle values. Let's arrange the given values and find the median. 13 , 16 , 19 , 20 | 22 , 25 , 30 , 31 Since there are 8 values, there is no one middle value. Therefore, the median is the mean of the two middle values. Median: 20+ 22/2=21

Mode

The mode is the value or values that appear most often in a set of data. Let's find the mode of the given values. 13 , 30 , 16 , 19 , 20 , 22 , 25 , 31 Since the data set does not contain any repeated values, there is no mode.

b The mode does not exist in this set. Therefore, it is not the measure that best represents the data.

ccc Mode & Median & Mean * & ? & ? Let's now consider the mean and the median. In the given list of numbers there are no obvious outliers. Both median and mean could represent the data. ccc Mode & Median & Mean * & âś“ & âś“ In such case we usually choose the mean.