body{margin:0;} noscript{z-index: 10000; position: fixed; display: block; height: 100%; width: 100%; background: #fff;} noscript .fa{font-size: 40px; display:block; color: #daa520;} noscript div{margin-top: 6%; padding-left: 20px; padding-right: 20px; text-align: center;} ! You must have JavaScript enabled to use this site.

Big Ideas Math Algebra 1, 2015

BI

Big Ideas Math Algebra 1, 2015 View details

3. Solving Radical Equations

Continue to next subchapter

Exercise 89 Page 566

Make a table of values to find points on the curve. Then plot and connect the points.

Graph:

Comparison to the Graph Of f(x)=x^2: There is a vertical stretch by a factor of 5 followed by a reflection in the x-axis of the graph of f.

Practice makes perfect

To graph the function we will make a table of values.

x	- 5x^2	h(x)=- 5x^2
- 2	- 5( - 2)^2	- 20
- 1	- 5( - 1)^2	- 5
0	- 5( 0)^2	0
1	- 5( 1)^2	- 5
2	- 5( 2)^2	- 20

Let's now draw the parabola that connects the obtained points. We will also draw the parent function f(x)=x^2.

From the graph above, we can note the following.

The graph of the given function opens down, and the graph of the parent function opens up.
Both graphs have the same axis of symmetry x=0.
The graph of the given function is narrower than the graph of the parent function.
Both graphs have the same vertex (0,0).

From the graph and the observations above, we can conclude that the graph of h is a vertical stretch by a factor of 5 of the graph of f, followed by a reflection in the x-axis.

Subchapter links

Communicate Your Answer p.559

Monitoring Progress p.560-563

Exercises p.564-566