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Wayne's the youngest brother — let's call his age $n.$ Thus, the age of the other two brothers can be expressed as $(n+1)$ and $(n+2).$ Using this and the fact that the sum of their ages is $96$ we get an equation.
$n+(n+1)+(n+2)=96 $
Let's solve for $n.$
Therefore, Wayne is $31$ years old, Gordie is $32,$ and Mario is $33.$

$n+(n+1)+(n+2)=96$

RemoveParRemove parentheses

$n+n+1+n+2=96$

AddTermsAdd terms

$3n+3=96$

SubEqn$LHS−3=RHS−3$

$3n=93$

DivEqn$LHS/3=RHS/3$

$n=31$