When , the first step is to rearrange the equation so that the term is isolated.
2∣x+1∣+6=8⇔∣x+1∣=1
The left-hand side of the equation can now be expressed as the f(x)=∣x+1∣. We'll draw its graph.
The solutions to the equation are the x-coordinates of the points on the graph that have y-coordinate 1.
The solutions of the equation are
x=-2 and
x=0. We can verify them by substituting in the given equation. We'll start with
x=-2.
2∣x+1∣+6=8 2∣-2+1∣+6=?8 2∣-1∣+6=?8 2(1)+6=?8 2+6=?8
8=8 ✓
Since
x=-2 makes a true statement, it is a solution to the equation. Next, we'll verify
x=1 in the same way.
2∣0+1∣+6=?8⇒8=8 ✓
Since
x=0 makes a true statement, it is also a solution. Therefore, both
x=-2 and
x=0 are solutions to the given equation.