2. Properties of Cylinders
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Chapter 3
2.
Properties of Cylinders
This lesson focuses on the geometric aspects of cylinders, covering topics like volume, surface area, and the role of Cavalieri's Principle. Practical examples include determining the volume of a test tube for a chemistry experiment or calculating the surface area of a cylindrical object like a can. The lesson also discusses the importance of understanding the circumference of a circle when dealing with cylinders. For instance, knowing the circumference can help in calculating the surface area accurately. The Cavalieri's Principle is highlighted as a fundamental concept that applies to cylinders, stating that two solids with the same height and cross-sectional area will have the same volume. This knowledge is particularly useful in fields like engineering, architecture, and science experiments.
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Lesson Settings & Tools
| | 14 Theory slides |
| | 11 Exercises - Grade E - A |
| | Each lesson is meant to take 1-2 classroom sessions |
Properties of Cylinders
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Investigating the Volume of Different Cylinders
Consider the three-dimensional figure given in the diagram. By dragging the point, the figure can be skewed. However, its height and the radius of the circles that make the base and the top of the cylinder remain the same. Think about the volume — space occupied — of the solid. Does the volume change when the solid is skewed?
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Definition of a Circle
Before moving on, the definition of a circle and some of its parts will be reviewed.
A circle is the set of all the points in a plane that are equidistant from a given point. There are a few particularly notable features of a circle.
- Center - The given point from which all points of the circle are equidistant. Circles are often named by their center point.
- Radius - A segment that connects the center and any point on the circle. Its length is usually represented algebraically by r.
- Diameter - A segment whose endpoints are on the circle and that passes through the center. Its length is usually represented algebraically by d.
- Circumference - The perimeter of a circle, usually represented algebraically by C.
circle O,since it is centered at O.
Next, the formula for calculating the circumference of a circle will be discussed.
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Circumference of a Circle
The circumference of a circle is calculated by multiplying its diameter by π.
C=π d
Since the diameter is twice the radius, the circumference of a circle can also be calculated by multiplying 2r by π.
C=2π r
Proof
Consider two circles and their respective diameters and circumferences.
C_B/C_A=d_B/d_A
▼
Rearrange equation
MultEqn
LHS * C_A=RHS* C_A
C_B=d_B/d_A(C_A)
DivEqn
.LHS /d_B.=.RHS /d_B.
C_B/d_B=1/d_A(C_A)
MoveRightFacToNumOne
1/b* a = a/b
C_B/d_B=C_A/d_A
C/d=π ⇒ C=π d
Finally, the formula for calculating the area of a circle will be seen.
Rule
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Area of a Circle
The area of a circle is the product of π and the square of its radius.
Proof
Informal JustificationA circle with radius r will be divided into a number of equally sized sectors. Then, the top and bottom halves of the circle will be distinguished by filling them with different colors. Because the circumference of a circle is 2 π r, the arc length of each semicircle is half this value, π r.
Now, the above sectors will be unfolded. By placing the sectors of the upper hemisphere as teeth pointing downwards and the sectors of the bottom hemisphere as teeth pointing upwards, a parallelogram-like figure can be formed. As such, the area of the figure below should be the same as the circle's area.
A = π r * r ⇔ A= π r^2
It has been shown that the area of a circle is the product of π and the square of its radius.
Example
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Finding the Circumference and Area of a Circle
Izabella loves to use geometry in her art. Her school noticed her skills and hired her to paint the school's soccer field — for a substantial payment. The diagram shows how the field should look.
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Hint
The circumference is twice the product of π and the radius. The area is the product of π and the square of the radius.
Solution
The circumference of a circle with radius r is twice the product of π and r. Furthermore, its area is the product of π and r^2. Since the radius is 6.5 meters, the circumference and area can be calculated.
| Formula | Substitute | Simplify | Approximate | |
|---|---|---|---|---|
| Circumference | C=2π r | C=2π ( 6.5) | C=13π | C≈ 40.8 |
| Area | A=π r^2 | A=π ( 6.5^2) | A=42.25π | A≈ 132.7 |
The circumference and area of the circle located at the center of the soccer field are about 40.8 meters and 132.7 square meters, respectively.
Example
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Investigating the Area of a Circle
Maya bought 20 meters of fencing with the hopes of constructing a circular dog run for her dog Opie. Because Opie is a large Saint Bernard, she wants the area of the dog run to be at least 30 square meters.
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Hint
Start by finding the radius of the circle.
Solution
Because the dog run is in the shape of a circle, its area is the product of π and the square of the radius. Therefore, to find the area of the circle, the first step is to find the radius. Since it is already known that the circumference is 20 meters, the formula for the circumference will be used to find the radius.
C=2π r
Since Maya bought and used 20 meters of fencing, the circumference measures 20 meters. This value can be substituted in the above formula to find the radius r.
The radius of Opie's circular dog run is about 3.18 meters. 
With this information, the area of the dog run can be calculated.
A=π r^2
To do so, 3.18 will be substituted for r in the formula for the area of a circle.
The area of Opie's dog run is about 31.8 square meters. This is enough for him to have happy and healthy playtime!
C=2π r
Substitute
C= 20
20=2π r
▼
Solve for r
DivEqn
.LHS /2.=.RHS /2.
10=π r
DivEqn
.LHS /π.=.RHS /π.
10/π=r
RearrangeEqn
Rearrange equation
r=10/π
UseCalc
Use a calculator
r=3.183098...
RoundSigDig
Round to 3 significant digit(s)
r≈ 3.18
A=π r^2
Substitute
r= 3.18
A=π ( 3.18^2)
▼
Evaluate right-hand side
CalcPow
Calculate power
A=π (10.1124)
Multiply
Multiply
A=31.769041
RoundSigDig
Round to 3 significant digit(s)
A≈ 31.8
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Practice Finding the Circumference and Area of a Circle
For the following questions, approximate the answers to one decimal place. Do not include units in the answer.
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Cavalieri's Principle
Now, two-dimensional figures will be left aside to move forward into solids, which are three-dimensional shapes.
Two solids with the same height and the same cross-sectional area at every altitude have the same volume. This means that, as long as their heights are equal, skewed versions of the same solid have the same volume.
If V_1 and V_2 are the volumes of the above solids, then they are equal.
V_1 = V_2
Proof
Informal JustificationThis principle will be proven by using a set of identical coins. Consider a stack in which each of these coins is placed directly on top of each other. Consider also another stack where the coins lie on top of each other, but are not aligned.
The first stack can be considered as a right cylinder. Similarly, the second stack can be considered as an oblique cylinder, which is a skewed version of the first cylinder. Because the coins are identical, the cross-sectional areas of the cylinders at the same altitude are the same.
Since the coins are identical, they have the same volume. Furthermore, since the height is the same for both stacks, they both have the same number of coins. Therefore, both stacks — cylinders — have the same volume. This reasoning is strongly based on the assumption that the face of the coins have the same area.
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Definition of a Cylinder
A cylinder is a three-dimensional figure that has two circular bases that are parallel and equal in size, connected by a curved surface.
Rule
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Volume of a Cylinder
The volume of a cylinder is calculated by multiplying the area of its base by its height.
If the radius of the base of a cylinder is r, the volume can be calculated by the following formula.
V=π r^2h
Proof
Informal JustificationConsider a rectangular prism and a right cylinder that have the same base area and height.
In this case, the cross-sections of the prism and the cylinder are congruent to their bases. Therefore, their cross-sectional areas at every altitude are equal.
By the Cavalieri's Principle, two solids with the same height and the same cross-sectional area at every altitude have the same volume. Therefore, the volume of the cylinder is the same as the volume of the prism. V_C=V_P Furthermore, the volume of a prism can be calculated by multiplying the area of its base by its height. V_P=Bh By the Transitive Property of Equality, a formula for the volume of the cylinder can be written. V_C= V_P V_P=Bh ⇒ V_C=Bh Finally, not only is B the area of the base of the prism, but also the area of the base of the cylinder. Since the base of the cylinder is a circle, its area is the product of π and the square of its radius r. Therefore, B=π r^2 can be substituted in the above formula. V_C=Bh substitute V_C= π r^2 h This formula applies to all cylinders because there is always a prism with the same base area and height. Also, by the Cavalieri's principle, this formula still holds true for oblique cylinders.
Example
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Finding the Volume of a Cylinder
LaShay loves golfing. She is about to buy a new golf bag.
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Hint
The volume of a cylinder is the product of π, the square of its radius, and its height.
Solution
The golf bag is in the shape of a cylinder. Therefore, to calculate its volume, the formula for the volume of a cylinder can be used.
V=π r^2h
SubstituteII
h= 132, r= 15
V=π ( 15^2)( 132)
▼
Evaluate right-hand side
CalcPow
Calculate power
V=π (225)(132)
Multiply
Multiply
V=29 700π
UseCalc
Use a calculator
V=93 305.30181...
RoundSigDig
Round to 3 significant digit(s)
V≈ 93 300
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Finding the Radius of a Cylinder
Kriz is making an experiment to complete a Chemistry project. He is using a test tube in the shape of a cylinder with a height of 75 millimeters and a volume of 20 000 cube millimeters.
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Solution
The volume of a cylinder is the product of π, the square of the base's radius, and the height of the cylinder.
V=π r^2 h
It is known that the height and the volume of the cylinder are 75 millimeters and 20 000 cube millimeters, respectively. These two values can be substituted into the formula for volume of a cylinder, which can then be solved for r.
When solving the equation, only the principal root was considered. This is because the radius of a circle is always positive. Therefore, the radius of the cylinder's base is about 9.2 millimeters. Since the radius is greater than 9 millimeters, the tube does not suit the experiment.
V=π r^2 h
SubstituteII
h= 75, V= 20 000
20 000=π r^2 ( 75)
▼
Solve for r
CommutativePropMult
Commutative Property of Multiplication
20 000=75π r^2
DivEqn
.LHS /75π.=.RHS /75π.
20 000/75π=r^2
SqrtEqn
sqrt(LHS)=sqrt(RHS)
sqrt(20 000/75π)=r
RearrangeEqn
Rearrange equation
r=sqrt(20 000/75π)
UseCalc
Use a calculator
r=9.213177...
RoundDec
Round to 1 decimal place(s)
r≈ 9.2
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Surface Area of a Cylinder
Besides the radius, height, and volume, another essential characteristic of a cylinder is its surface area. The surface area of a solid is the measure of the total area that the surface of the solid occupies.
Consider a cylinder of height h and radius r.
The surface area of this cylinder is given by the following formula.
S=2π rh+2π r^2
Proof
The cylinder's surface area can be seen as three separate parts that are top, bottom, and side. The area of the side has the shape of a rectangle of width h. The top and the bottom are circles of radius r.
Since the top and the bottom are congruent circles, they have the same area. cc Area of & Area of One Circle & Two Circles [0.8em] A=π r^2 & A=2π r^2 To find the area of the rectangle, its length must be found first. The length of the rectangle that forms the lateral part of the cylinder is the circumference of the base, which is 2π r.
Therefore, the area of the rectangle is the product of h and 2π r. Area of the Rectangle A=2π rh The surface area of the cylinder S is the sum of the areas of the rectangle and the circles.
S=2π rh+2π r^2
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Finding the Surface Area of a Cylinder
Jordan's father is giving her a new baseball bat for her birthday. To avoid damage to the bat, Papa Jordan will store the bat in a box that has the shape of a cylinder with a height of 30 inches and a radius of 1.6 inches. Since this is a present for Jordan, Papa will use wrapping paper to make it even more special.
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Hint
The area of wrapping paper Jordan's father needs is the same as the surface area of the cylinder.
Solution
To find the minimum area of paper that Jordan's father needs, the surface area S of the cylinder needs to be calculated.
S=2π rh+2π r^2
Here, r and h are the radius and the height of the cylinder, respectively. The radius is 1.6 inches and the height is 30 inches. Therefore, these values can be substituted in the above formula, which can then be simplified.
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Practice Finding the Surface Area and Volume of a Cylinder
Find the volume or surface area of the cylinder.
Closure
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Volume of Skewed Solids
The challenge presented at the beginning of this lesson asked whether the volume of a cylinder changes if the solid is skewed.
The Cavalieri's Principle was studied in this lesson. This principle states that two solids with the same height and the same cross-sectional area at every altitude have the same volume. Therefore, if their heights are equal, skewed versions of the same solid have the same volume. This means that the volume of a cylinder does not change even if the cylinder is skewed.
Properties of Cylinders
Exercises
The volume of a cylinder with radius r and height h is the product of π, the square of r, and h.
V=π r^2 h
Calculate the height of a cylinder with a radius of 3.1 centimeters and a volume of 330 cubic centimeters. Round to the nearest centimeter.
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Let's substitute r=3.1 and V=330 into the given formula, and solve for h.
The cylinder has a height of about 11 centimeters.
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Determine the missing dimension of the cylinder.
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The volume of a cylinder with radius r and height h is the product of π, the square of r, and h. V=π r^2 h In this case, we know that the volume is V= 24π and the radius is r= 2. Let's substitute these values in the formula and solve for h.
The height of the cylinder is 6 feet.
This time, we have been given the height and volume and want to solve for the radius of the cylinder. Remember that a length can never be negative, so we will disregard any negative solutions.
The radius of the cylinder is 5 feet.
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Determine the volume of the cylinder. Write the answer in exact form.
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The volume of a cylinder with radius r and height h is the product of π, the square of r, and h. V=π r^2 h Since we are given both the radius and height of the cylinder, we can substitute them into the formula to determine the volume.
To calculate the volume of this cylinder, we use the same formula as in the previous section.
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Determine the volume of the cylinder. Write the answer in exact form.
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The volume of a cylinder with radius r and height h is the product of π, the square of the r, and h. V=π r^2 h According to Cavalieri's Principle, it does not matter whether the cylinder is right or oblique. Therefore, although we are given an oblique cylinder, we can use the same formula.
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Calculate the surface area of the cylinder. Write the answer in exact form.
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The surface area of a cylinder is the sum of the areas of its circular bases and the area of its lateral surface. The lateral surface is a rolled up rectangle whose length is the same as the circumference of the cylinder's base and whose width is the same as the cylinder's height.
With this information, we can write the formula for the surface area of a cylinder. SA=2π rh+2π r^2 Let's substitute the height and radius of the given cylinder into this formula.
We will use the same formula for calculating the surface area of the cylinder.
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Properties of Cylinders
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